1968 Missouri Attorney General election
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November 5, 1968
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| Elections in Missouri |
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The 1968 Missouri Attorney General election was held on November 5, 1968, in order to elect the attorney general of Missouri. Republican nominee John Danforth defeated Democratic nominee and incumbent attorney general Norman H. Anderson.[1]
General election
[edit]On election day, November 5, 1968, Republican nominee John Danforth won the election by a margin of 72,133 votes against his opponent Democratic nominee Norman H. Anderson, thereby gaining Republican control over the office of attorney general. Danforth was sworn in as the 37th attorney general of Missouri on January 13, 1969.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | John Danforth | 891,498 | 52.11 | |
| Democratic | Norman H. Anderson (incumbent) | 819,365 | 47.89 | |
| Total votes | 1,710,863 | 100.00 | ||
| Republican gain from Democratic | ||||
See also
[edit]References
[edit]- ↑ "1968 Attorney General General Election Results - Missouri". uselectionatlas.org. April 24, 2007. Retrieved 2024-10-27.
- ↑ "MO Attorney General". ourcampaigns.com. February 11, 2021. Retrieved 2024-10-27.