Enumerable.Min Method

Source:

Min.cs

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Min.cs

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public:
[System::Runtime::CompilerServices::Extension]
 static float Min(System::Collections::Generic::IEnumerable ^ source);

public static float Min(this System.Collections.Generic.IEnumerable source);

static member Min : seq -> single

Public Function Min (source As IEnumerable(Of Single)) As Single

Parameters

Returns

The minimum value in the sequence.

Exceptions

Remarks

The Min(IEnumerable) method uses the Single implementation of IComparable to compare values.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

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Min.cs

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Min.cs

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable Min(System::Collections::Generic::IEnumerable> ^ source);

public static float? Min(this System.Collections.Generic.IEnumerable source);

static member Min : seq> -> Nullable

Public Function Min (source As IEnumerable(Of Nullable(Of Single))) As Nullable(Of Single)

Parameters

Returns

The value that corresponds to the minimum value in the sequence.

Exceptions

Remarks

The Min(IEnumerable>) method uses the Single implementation of IComparable to compare values.

If the source sequence is empty or contains only values that are null, this function returns null.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

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Min.cs

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Min.cs

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Min.cs

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable Min(System::Collections::Generic::IEnumerable> ^ source);

public static int? Min(this System.Collections.Generic.IEnumerable source);

static member Min : seq> -> Nullable

Public Function Min (source As IEnumerable(Of Nullable(Of Integer))) As Nullable(Of Integer)

Parameters

Returns

The value that corresponds to the minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable>) to determine the minimum value in a sequence.

int?[] grades = { 78, 92, null, 99, 37, 81 };

int? min = grades.Min();

Console.WriteLine("The lowest grade is {0}.", min);

/*
 This code produces the following output:

 The lowest grade is 37.
*/

Dim grades() As Nullable(Of Integer) = {78, 92, Nothing, 99, 37, 81}
Dim min As Nullable(Of Integer) = grades.Min()

' Display the output.
Console.WriteLine($"The lowest grade is {min}")

' This code produces the following output:
'
' The lowest grade is 37

Remarks

The Min(IEnumerable>) method uses the Int32 implementation of IComparable to compare values.

If the source sequence is empty or contains only values that are null, this function returns null.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

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Min.cs

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Min.cs

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Min.cs

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable Min(System::Collections::Generic::IEnumerable> ^ source);

public static double? Min(this System.Collections.Generic.IEnumerable source);

static member Min : seq> -> Nullable

Public Function Min (source As IEnumerable(Of Nullable(Of Double))) As Nullable(Of Double)

Parameters

Returns

The value that corresponds to the minimum value in the sequence.

Exceptions

Remarks

The Min(IEnumerable>) method uses the Double implementation of IComparable to compare values.

If the source sequence is empty or contains only values that are null, this function returns null.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

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Min.cs

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Min.cs

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable Min(System::Collections::Generic::IEnumerable> ^ source);

public static long? Min(this System.Collections.Generic.IEnumerable source);

static member Min : seq> -> Nullable

Public Function Min (source As IEnumerable(Of Nullable(Of Long))) As Nullable(Of Long)

Parameters

Returns

The value that corresponds to the minimum value in the sequence.

Exceptions

Remarks

The Min(IEnumerable>) method uses the Int64 implementation of IComparable to compare values.

If the source sequence is empty or contains only values that are null, this function returns null.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

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Min.cs

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Min.cs

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Min.cs

public:
[System::Runtime::CompilerServices::Extension]
 static long Min(System::Collections::Generic::IEnumerable ^ source);

public static long Min(this System.Collections.Generic.IEnumerable source);

static member Min : seq -> int64

Public Function Min (source As IEnumerable(Of Long)) As Long

Parameters

Returns

The minimum value in the sequence.

Exceptions

Remarks

The Min(IEnumerable) method uses the Int64 implementation of IComparable to compare values.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

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Min.cs

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Min.cs

public:
[System::Runtime::CompilerServices::Extension]
 static int Min(System::Collections::Generic::IEnumerable ^ source);

public static int Min(this System.Collections.Generic.IEnumerable source);

static member Min : seq -> int

Public Function Min (source As IEnumerable(Of Integer)) As Integer

Parameters

Returns

The minimum value in the sequence.

Exceptions

Remarks

The Min(IEnumerable) method uses the Int32 implementation of IComparable to compare values.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

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Min.cs

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Min.cs

public:
[System::Runtime::CompilerServices::Extension]
 static double Min(System::Collections::Generic::IEnumerable ^ source);

public static double Min(this System.Collections.Generic.IEnumerable source);

static member Min : seq -> double

Public Function Min (source As IEnumerable(Of Double)) As Double

Parameters

Returns

The minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable) to determine the minimum value in a sequence.

double[] doubles = { 1.5E+104, 9E+103, -2E+103 };

double min = doubles.Min();

Console.WriteLine("The smallest number is {0}.", min);

/*
 This code produces the following output:

 The smallest number is -2E+103.
*/

' Create an array of double values.
Dim doubles() As Double = {1.5E+104, 9.0E+103, -2.0E+103}

' Determine the smallest number in the array.
Dim min As Double = doubles.Min()

' Display the result.
Console.WriteLine($"The smallest number is {min}")

' This code produces the following output:
'
' The smallest number is -2E+103

Remarks

The Min(IEnumerable) method uses the Double implementation of IComparable to compare values.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

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Min.cs

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Min.cs

public:
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Min(System::Collections::Generic::IEnumerable ^ source);

public static decimal Min(this System.Collections.Generic.IEnumerable source);

static member Min : seq -> decimal

Public Function Min (source As IEnumerable(Of Decimal)) As Decimal

Parameters

Returns

The minimum value in the sequence.

Exceptions

Remarks

The Min(IEnumerable) method uses the Decimal implementation of IComparable to compare values.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

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Min.cs

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Min.cs

public:
[System::Runtime::CompilerServices::Extension]
 static Nullable Min(System::Collections::Generic::IEnumerable> ^ source);

public static decimal? Min(this System.Collections.Generic.IEnumerable source);

static member Min : seq> -> Nullable

Public Function Min (source As IEnumerable(Of Nullable(Of Decimal))) As Nullable(Of Decimal)

Parameters

Returns

The value that corresponds to the minimum value in the sequence.

Exceptions

Remarks

The Min(IEnumerable>) method uses the Decimal implementation of IComparable to compare values.

If the source sequence is empty or contains only values that are null, this function returns null.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

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Min.cs

public:
generic 
[System::Runtime::CompilerServices::Extension]
 static TResult Min(System::Collections::Generic::IEnumerable ^ source, Func ^ selector);

public static TResult Min(this System.Collections.Generic.IEnumerable source, Func selector);

public static TResult? Min(this System.Collections.Generic.IEnumerable source, Func selector);

static member Min : seq<'Source> * Func<'Source, 'Result> -> 'Result

Public Function Min(Of TSource, TResult) (source As IEnumerable(Of TSource), selector As Func(Of TSource, TResult)) As TResult

Type Parameters

Parameters

Returns

The minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable, Func) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

Remarks

If type TResult implements IComparable, this method uses that implementation to compare values. Otherwise, if type TResult implements IComparable, that implementation is used to compare values.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• MinBy method
• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

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Min.cs

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Min.cs

public:
generic 
[System::Runtime::CompilerServices::Extension]
 static Nullable Min(System::Collections::Generic::IEnumerable ^ source, Func> ^ selector);

public static int? Min(this System.Collections.Generic.IEnumerable source, Func selector);

static member Min : seq<'Source> * Func<'Source, Nullable> -> Nullable

Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Integer))) As Nullable(Of Integer)

Type Parameters

Parameters

Returns

The value that corresponds to the minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable, Func) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

Remarks

The Min(IEnumerable, Func>) method uses the Int32 implementation of IComparable to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable in C# or Nullable(Of Int32) in Visual Basic.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

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Min.cs

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Min.cs

Source:

Min.cs

public:
generic 
[System::Runtime::CompilerServices::Extension]
 static float Min(System::Collections::Generic::IEnumerable ^ source, Func ^ selector);

public static float Min(this System.Collections.Generic.IEnumerable source, Func selector);

static member Min : seq<'Source> * Func<'Source, single> -> single

Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Single)) As Single

Type Parameters

Parameters

Returns

The minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable, Func) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

Remarks

The Min(IEnumerable, Func) method uses the Single implementation of IComparable to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Single.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

public:
generic 
[System::Runtime::CompilerServices::Extension]
 static Nullable Min(System::Collections::Generic::IEnumerable ^ source, Func> ^ selector);

public static float? Min(this System.Collections.Generic.IEnumerable source, Func selector);

static member Min : seq<'Source> * Func<'Source, Nullable> -> Nullable

Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Single))) As Nullable(Of Single)

Type Parameters

Parameters

Returns

The value that corresponds to the minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable, Func) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

Remarks

The Min(IEnumerable, Func>) method uses the Single implementation of IComparable to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable in C# or Nullable(Of Single) in Visual Basic.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

public:
generic 
[System::Runtime::CompilerServices::Extension]
 static Nullable Min(System::Collections::Generic::IEnumerable ^ source, Func> ^ selector);

public static long? Min(this System.Collections.Generic.IEnumerable source, Func selector);

static member Min : seq<'Source> * Func<'Source, Nullable> -> Nullable

Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Long))) As Nullable(Of Long)

Type Parameters

Parameters

Returns

The value that corresponds to the minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable, Func) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

Remarks

The Min(IEnumerable, Func>) method uses the Int64 implementation of IComparable to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable in C# or Nullable(Of Int64) in Visual Basic.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

public:
generic 
[System::Runtime::CompilerServices::Extension]
 static Nullable Min(System::Collections::Generic::IEnumerable ^ source, Func> ^ selector);

public static double? Min(this System.Collections.Generic.IEnumerable source, Func selector);

static member Min : seq<'Source> * Func<'Source, Nullable> -> Nullable

Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Double))) As Nullable(Of Double)

Type Parameters

Parameters

Returns

The value that corresponds to the minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable, Func) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

Remarks

The Min(IEnumerable, Func>) method uses the Double implementation of IComparable to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable in C# or Nullable(Of Double) in Visual Basic.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

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Min.cs

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Min.cs

Source:

Min.cs

public:
generic 
[System::Runtime::CompilerServices::Extension]
 static System::Decimal Min(System::Collections::Generic::IEnumerable ^ source, Func ^ selector);

public static decimal Min(this System.Collections.Generic.IEnumerable source, Func selector);

static member Min : seq<'Source> * Func<'Source, decimal> -> decimal

Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Decimal)) As Decimal

Type Parameters

Parameters

Returns

The minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable, Func) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

Remarks

The Min(IEnumerable, Func) method uses the Decimal implementation of IComparable to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Decimal.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

public:
generic 
[System::Runtime::CompilerServices::Extension]
 static long Min(System::Collections::Generic::IEnumerable ^ source, Func ^ selector);

public static long Min(this System.Collections.Generic.IEnumerable source, Func selector);

static member Min : seq<'Source> * Func<'Source, int64> -> int64

Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Long)) As Long

Type Parameters

Parameters

Returns

The minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable, Func) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

Remarks

The Min(IEnumerable, Func) method uses the Int64 implementation of IComparable to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int64.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

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Min.cs

Source:

Min.cs

public:
generic 
[System::Runtime::CompilerServices::Extension]
 static int Min(System::Collections::Generic::IEnumerable ^ source, Func ^ selector);

public static int Min(this System.Collections.Generic.IEnumerable source, Func selector);

static member Min : seq<'Source> * Func<'Source, int> -> int

Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Integer)) As Integer

Type Parameters

Parameters

Returns

The minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable, Func) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

Remarks

The Min(IEnumerable, Func) method uses the Int32 implementation of IComparable to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int32.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

public:
generic 
[System::Runtime::CompilerServices::Extension]
 static double Min(System::Collections::Generic::IEnumerable ^ source, Func ^ selector);

public static double Min(this System.Collections.Generic.IEnumerable source, Func selector);

static member Min : seq<'Source> * Func<'Source, double> -> double

Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Double)) As Double

Type Parameters

Parameters

Returns

The minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable, Func) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

Remarks

The Min(IEnumerable, Func) method uses the Double implementation of IComparable to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Double.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

public:
generic 
[System::Runtime::CompilerServices::Extension]
 static TSource Min(System::Collections::Generic::IEnumerable ^ source, System::Collections::Generic::IComparer ^ comparer);

public static TSource? Min(this System.Collections.Generic.IEnumerable source, System.Collections.Generic.IComparer? comparer);

static member Min : seq<'Source> * System.Collections.Generic.IComparer<'Source> -> 'Source

Public Function Min(Of TSource) (source As IEnumerable(Of TSource), comparer As IComparer(Of TSource)) As TSource

Type Parameters

Parameters

Returns

The minimum value in the sequence.

Exceptions

Remarks

If type TSource implements IComparable, the Max(IEnumerable) method uses that implementation to compare values. Otherwise, if type TSource implements IComparable, that implementation is used to compare values.

If TSource is a reference type and the source sequence is empty or contains only values that are null, this method returns null.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

public:
generic 
[System::Runtime::CompilerServices::Extension]
 static TSource Min(System::Collections::Generic::IEnumerable ^ source);

public static TSource Min(this System.Collections.Generic.IEnumerable source);

public static TSource? Min(this System.Collections.Generic.IEnumerable source);

static member Min : seq<'Source> -> 'Source

Public Function Min(Of TSource) (source As IEnumerable(Of TSource)) As TSource

Type Parameters

Parameters

Returns

The minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable) to determine the minimum value in a sequence of IComparable objects.

/// 

/// This class implements IComparable in order to
/// be able to compare different Pet objects.
/// 
class Pet : IComparable
{
    public string Name { get; set; }
    public int Age { get; set; }

    /// 

    /// Compares this Pet's age to another Pet's age.
    /// 
    /// The Pet to compare this Pet to.
    /// -1 if this Pet's age is smaller,
    /// 0 if the Pets' ages are equal, or
    /// 1 if this Pet's age is greater.
    int IComparable.CompareTo(Pet other)
    {
        if (other.Age > this.Age)
            return -1;
        else if (other.Age == this.Age)
            return 0;
        else
            return 1;
    }
}

public static void MinEx3()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    Pet min = pets.Min();

    Console.WriteLine(
        "The 'minimum' animal is {0}.",
        min.Name);
}

/*
 This code produces the following output:

 The 'minimum' animal is Whiskers.
*/

' This class implements IComparable
' and has a custom 'CompareTo' implementation.
Class Pet
    Implements IComparable(Of Pet)

    Public Name As String
    Public Age As Integer

    ''' 

    ''' Compares this Pet's age to another Pet's age.
    ''' 
    ''' The Pet to compare this Pet to.
    ''' -1 if this Pet's age is smaller,
    ''' 0 if the Pets' ages are equal,
    ''' or 1 if this Pet's age is greater.
    Function CompareTo(ByVal other As Pet) As Integer _
    Implements IComparable(Of Pet).CompareTo

        If (other.Age > Me.Age) Then
            Return -1
        ElseIf (other.Age = Me.Age) Then
            Return 0
        Else
            Return 1
        End If
    End Function
End Class

Sub MinEx3()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "minimum" pet in the array,
    ' according to the custom CompareTo() implementation.
    Dim min As Pet = pets.Min()

    ' Display the result.
    Console.WriteLine($"The 'minimum' pet is {min.Name}")
End Sub

' This code produces the following output:
'
' The 'minimum' pet is Whiskers

Remarks

If type TSource implements IComparable, this method uses that implementation to compare values. Otherwise, if type TSource implements IComparable, that implementation is used to compare values.

If TSource is a reference type and the source sequence is empty or contains only values that are null, this function returns null.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

Source:

Min.cs

public:
generic 
[System::Runtime::CompilerServices::Extension]
 static Nullable Min(System::Collections::Generic::IEnumerable ^ source, Func> ^ selector);

public static decimal? Min(this System.Collections.Generic.IEnumerable source, Func selector);

static member Min : seq<'Source> * Func<'Source, Nullable> -> Nullable

Public Function Min(Of TSource) (source As IEnumerable(Of TSource), selector As Func(Of TSource, Nullable(Of Decimal))) As Nullable(Of Decimal)

Type Parameters

Parameters

Returns

The value that corresponds to the minimum value in the sequence.

Exceptions

Examples

The following code example demonstrates how to use Min(IEnumerable, Func) to determine the minimum value in a sequence of projected values.

class Pet
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void MinEx4()
{
    Pet[] pets = { new Pet { Name="Barley", Age=8 },
                   new Pet { Name="Boots", Age=4 },
                   new Pet { Name="Whiskers", Age=1 } };

    int min = pets.Min(pet => pet.Age);

    Console.WriteLine("The youngest animal is age {0}.", min);
}

/*
 This code produces the following output:

 The youngest animal is age 1.
*/

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub

' This code produces the following output:
'
' The youngest pet is age 1

Remarks

The Min(IEnumerable, Func>) method uses the Decimal implementation of IComparable to compare values.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable in C# or Nullable(Of Decimal) in Visual Basic.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

See also

• Aggregate Clause (Visual Basic)